Question

A torque of 10 Nm is applied on a wheel having angular momentum of `2 kg m^(2)s^(-1)`, calculate the angular momentum of the wheel after 4 seconds.

Answer 1

Torque, `tau=(dL)/(dt)rArr tau=(L_(2)-L_(1))/(t)`
Angular moment of the wheel,
`L_(2)=taut+L_(1)=10xx4+2=40+2=42 "kgm"^(2)s^(-1)`.