Question

A particle is projected from horizontal ground with speed `5ms^(-1)` at `53^(@)` with horizontal. Find time after which velocity of particle will be `45^(@)` with horizontal:
A. `(1)/(10)` sec
B. `(3)/(10)` sec
C. `(5)/(10)` sec
D. `(7)/(10)` sec

Answer 1

Correct Answer - a,d

`5cos 53^(@)=v cos 45^(@)`
`v sin 45^(@)=5sin 53^(@)-gt`