Question

Three forces are acting on a particle of mass m initially in equilibrium if the first two forces `(vec(R)_(1)and vec(R)_(2))` are perpendicular to each other and suddenly the third force `(vec(R)_(3))` is removed, then the magnitude of acceleration of the particle is:
A. `1/m|vec(R)_(2)|`
B. `1/m|vec(R)_(1)+vec(R)_(2)|`
C. `1/m|vec(R)_(1)-vec(R)_(2)|`
D. `1/m|vec(R)_(1)|`

Answer 1

Correct Answer - B
`vec(a)=(vecF_("net"))/M=((vec(R_(1))+vec(R_(2)))/m)`