In the arrangement shown below pulleys are mass less and frictionless and threads are in responsible block of mass `m_(1)` will remain at rest if :
A. `4/m_(1)=1/m_(2)+1/m_(3)`
B. `m_(1)=m_(2)=m_(3)`
C. `1/m_(1)=1/m_(2)+1/m_(3)`
D. `1/m_(3)=2/m_(2)+3/m_(1)`
