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(a) वेग ` = sqrt (("दाब")/(x)) `, तो x की विमाए लिखिए |
` T = 2 pi sqrt ( LY ) ` में T समय है तो Y की विमाए ज्ञात कीजिये |

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(a) वेग = `sqrt (("दाब")/(x )) ` ,
अतः ` x = (" दाब")/(("वेग")^(2 )) `
विमीय रूपों में लिखने पर
` [x] = ( [ ML^(-1 ) T ^( - 2 ) ])/( [LT ^( - 1) ]^(2)) = [ ML ^( - 3 ) T ^( 0 )]`
अतः x की विमिये `M, L ` व T में ` ( 1, - 3, 0 ) ` है |
(b) ` T = 2pi sqrt ( LY) `
अतः ` Y = ( 1 ) /( 4pi ^(2))* ( T ^(2))/(L ) `
विमीय रूप में लिखने पर - (माना L लम्बाई है )
`[Y] = ([T]^(2))/([L]) = [M^(0) L ^( - 1 ) T ^( 2 ) ] `
अतः Y की विमाए M, L व T में ` (0, -1, 2 ) ` है |

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