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Two circles of radii a and b touch each other externally and `theta` be the angle between their direct common tangents `(agtbge2)`then

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Two circles of radii a and b touch each other externally and `theta` be the angle between their direct common tangents `(agtbge2)`then
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`C_1C_2BD` is a parallelogram
BD=a+b
AD=a-b
`sintheta/2=(AD)/(BD)=(a-b)/(a+b)` `theta/2=sin^(-1)((a-b)/(a+b))`
`theta=2sin^(-1)((a-b)/(a+b))`
option d is correct.
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