Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Sets, Relations and Functions by (93.6k points)
closed by
Find the value of `x` in `[-pi,pi]` for which `f(x)=sqrt((log)_2(4sin^2x-2sqrt(3)sinx-2sinx+sqrt(3)+1))` is defined.

1 Answer

0 votes
by (94.6k points)
selected by
 
Best answer
Correct Answer - `x in [-pi,(pi)/(6)] cup [(pi)/(3),(2pi)/(3)] cup [(5pi)/(6),pi]`
`f(x)=sqrt(log_(2)(4sin^(2)x-2sqrt(3)sinx-2sinx+sqrt(3)+1))` is defined if
`log_(2)(4sin^(2)x-2sqrt(3)sinx-2sinx+sqrt(3)+1) ge 0`
or `4sin^(2)x-2sinx(sqrt(3)+1)+sqrt(3)+1 ge 1`
or ` sin^(2)x-sinx ((sqrt(3))/(2)+(1)/(2)) +(sqrt(3))/(4) ge 0`
or ` (sinx-(sqrt(3))/(2)))(sinx-(1)/(2)) ge 0`
i.e., `-1 le sinx le (1)/(2) " or " (sqrt(3))/(2) le sinx le 1`
or `x in [-pi,(pi)/(6)] cup [(pi)/(3),(2pi)/(3)] cup [(5pi)/(6),pi]`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...