Question

A cylindrical can, whose base is horizontal and of radius 3.5 cm, contains sufficient water so that when a sphere is placed in the can, the water just covers the sphere. Given that the sphere just fits into the can, calculate:

(i) the total surface area of the can in contact with water when the sphere is in it;

(ii) the depth of water in the can before the sphere was put into the can.

Answer 1

Radius of the base of the cylindrical can = 3.5 cm

(i) When the sphere is in can, then total surface area of the can = Base area + curved surface area

(ii) Let depth of water = x cm

When sphere is not in the can, then volume of the can = volume of water + volume of sphere