Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Sets, Relations and Functions by (93.6k points)
closed by
The domain of the function `f(x)=sqrt("In"_((|x|-1))(x^(2)+4x+4))` is
A. `[-3,-1] cup [1,2]`
B. `(-2, -1) cup [2,oo)`
C. `(-oo,-3] cup (-2,-1) cup (2,oo)`
D. None of these

1 Answer

0 votes
by (94.6k points)
selected by
 
Best answer
Correct Answer - C
Case I:
` 0 lt |x|-1 lt 1 " or " 1 lt |x| lt 2`
Then `x^(2)+4x+4 le 1`
or `x^(2)+4x+3 le 0`
or `-3 le x le -1`
So, `x in (-2,-1) " (1)" `
Case II:
` |x|-1 gt 1 " or " |x| gt 2`
Then `x^(2)+4x+4 ge 1`
or `x^(2)+4x+3 ge 0`
or `x ge -1 " or " x le -3`
So, ` x in (-oo, -3] cup (2,oo)`
So, ` x in (-oo, -3] cup (2,oo) " (2) " `
From (1) and (2), ` x in (-oo, -3] cup (-2, -1) cup (2,oo)`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...