Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.8k views
in Parabola by (93.6k points)
closed by
The locus of centroid of triangle formed by a tangent to the parabola `y^(2) = 36x` with coordinate axes is
A. `y^(2) =- 9x`
B. `y^(2) +3x = 0`
C. `y^(2) = 3x`
D. `y^(2) = 9x`

1 Answer

0 votes
by (94.6k points)
selected by
 
Best answer
Correct Answer - B
Equation of tangent to `y^(2) = 36x` at `(x_(1),y_(1))` is
`y y_(1) = 18 (x+x_(1))`
It meets axis at `A(-x_(1),0)` and `B (0,(18x_(1))/(y_(1)))`.
`:.` Centroid of `DeltaOAB, (x,y) = ((-x_(1))/(3),(6x_(1))/(y_(1)))`
`:. x_(1) =- 3x` and `y_(1) = (6x_(1))/(y)`
Since, `(x_(1),y_(1))` lies on parabola, we have
`36x_(1) = (36x_(1)^(2))/(y^(2))`
`:. y^(2) = x_(1) rArr y^(2) =- 3x`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...