Correct Answer - D
Let `theta = cos^(-1) ((-1)/(sqrt(5))) rArr cos theta = (-1)/(sqrt(5)) rArr tan theta =-2`
Foci are `(+- 5,0)`
Equation of line through `(-5,0)` with slope `-2` is `y =- 2(x+5)` or `y =- 2x -10`
This line meets the ellipse above X-axis at `(-6,2)`
Reflected ray passes through the other focus `(5,0)`
`:.` Slope `= (2-0)/(-6-5) =- (2)/(11)`