Question

Calculate magnitude of `DeltaH` in calorie for 1 mol of an ideal gas undergoing adiabatic reversible process from 8 atm, 300 K to 2 atm. (Given : `gamma=2, R=2Cal//K//mol`)

Answer 1

[0600]
`(T_(2))/(T_(1))=((P_(1))/(P_(2)))^((1-gamma)/(gamma))=((8)/(2))^((1-2)/(2))=((4)/(1))^((-1)/(2))=((4)/(1))^((1)/(2))=(1)/(2)`
`T_(2)=150K`
`DeltaH=1xx(gammaR)/(gamma-1)(-150)=(2xx2)/(1)xx(-150)=-600`