Question

An element exists in bcc lattice with a cell edge of 288 pm. Calculate its molar density is `7.2g//cm^(3)`

Answer 1

(ii) BCC lattice. Hence `z=2`
`a=288p m=288xx10^(-12)m`
`d=7.2g//cm^(3)`
`d=(ZxxM)/(a^(3)xxNa)impliesM=(d xx a^(3)xxNa)/(Z)`
`M=(7.2xx(288xx10^(-10))xx6.022xx10^(23))/(2)`
`M=3.6xx288xx288xx288xx10^(-7)xx6.022`
`M=51.8g//mol`