Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
168 views
in Mathematics by (94.6k points)
closed by
If both the roots of the quadratic equation `x^(2) mx+4=0` are real and distinct and they lie in the interval `[1,5]` then m lies in the interval
A. `(4,5)`
B. `(-5,-4)`
C. `(5,6)`
D. `(3,4)`

1 Answer

0 votes
by (93.6k points)
selected by
 
Best answer
Correct Answer - A
According to given information, we have the following graph
image
Now, the folowing conditions should satisfy
`(i) Dgt0impliesb^(2)-4ac gt0`
`impliesm^(2)-4xx1xx4gt0`
`implies m^(2)-16gt0`
`implies(m-4)(m+4)gt0`
`impliesm in (-oo,-4)uu(4,oo)`
(ii) The value of the parabola should lie between `x=1and x=5`
`therefore-(b)/(2a)in(1,5)impliesltm/2lt5impliesm in (2,10)`
(iii) `f(I)gt0implies1-m+4 gt 0`
`impliesmlt5impliesm in (-oo,5)`
(iv) `f(5)gt0implies25-5m+4gt0implies5mlt29impliesm in(-oo,(29)/(5))`
From the values of m obtained in (i),(ii),(iii),and (iv), we get `m in (4,5).`
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...