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If `P=(x , y),F_1=(3,0),F_2=(-3,0),` and `16 x^2+25 y^2=400` , then `P F_1+P F_2` equal 8 (b) 6 (c) 10 (d) 12
A. 8
B. 6
C. 10
D. 12

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Correct Answer - C
given `16x^(2)+25y^(2)=400`
`implies (x^(2))/(25+(y^(2))/(16)=1`
Now, `PF_(1)+Pf_(2)= " Major axis = 2a` [ where , a=5]
`=2xx5=10`

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