Question

The heat of combustion of ethanol determinal in a bomb calorimeter is -670.48 K. Cals `"mole"^(-1)` at `25^(@)C`. What is `Delta H` at `25^(@)C` for the reaction :-
A. `-335.24` K. Cals.
B. `-671.08` K. Cals.
C. `-670.48` K. Cals.
D. `+670.48` K. Cals.

Answer 1

Correct Answer - B
`C_(2)H_(5)OH_((l))+3O_(2(g))rarr 2CO_(2(g))+3H_(2)O_((l))`
In Bomb calorimeter `Delta E = 670.48 kCal mol^(-1)`
`Delta H=Delta E + Delta n_(g)RT`
`Delta H=-670.48-1xx2xx10^(-3)xx298`