Correct Answer - `04.5`
In the circuit shown below all the currents are indicated which can be obtained by KCL at all junctions.
Writing KVL equation in closed loop we have
`+100-30-35-2R=0`
`implies 2R=35 V=V_(R)`
`implies V_(5 Omega)=7xx5=35 V`
`implies V_(5 Omega)/V_(R)=1`