Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
72 views
in Mathematics by (95.5k points)
closed by
In the circuit ......................

1 Answer

0 votes
by (94.9k points)
selected by
 
Best answer
Correct Answer - `04.5`
In the circuit shown below all the currents are indicated which can be obtained by KCL at all junctions.
Writing KVL equation in closed loop we have
`+100-30-35-2R=0`
`implies 2R=35 V=V_(R)`
`implies V_(5 Omega)=7xx5=35 V`
`implies V_(5 Omega)/V_(R)=1`

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...