Question

$ Addition of `NH_(4)OH` to an aqueous solution of `BaCl_(2)` in the presence of `NH_(4)Cl` (excess) precipitates `Ba(OH)_(2)`.
! `Ba(OH)_(2)` is insoluble in water.
A. Both A and R are true and R is the correct explanation of A
B. Both A and R are true but R is not a correct explanation of A
C. A is true but R is false
D. A is false but R is true.

Answer 1

Addition of `NH_(4)OH` to an aqueous solution of `BaCl_2` in the presence `NH_(4)Cl` (excess) does not give a precipitate of `Ba(OH)_(2)` as `Ba(OH)_2` is soluble in water.