(i) From the tables, it is clear that tan 13° 36’ = 0.2419
Hence, θ = 13° 36’
(ii) From the tables, it is clear that tan 25° 18’ = 0.4727
tan θ − tan 25° 18’ = 0.4741 − 0.4727 = 0.0014
From the tables, diff of 4’ = 0.0014
Hence, θ = 25° 18’ + 4’ = 25° 22’
(iii) From the tables, it is clear that tan 36° 24’ = 0.7373
tan θ − tan 36° 24’ = 0.7391 − 0.7373 = 0.0018
From the tables, diff of 4’ = 0.0018
Hence, θ = 36° 24’ + 4’ = 36° 28’