Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
103 views
in Mathematics by (91.8k points)
closed by
Find the range of values of `m` for which the line `y=m x+2` cuts the circle `x^2+y^2=1` at distinct or coincident points.

1 Answer

0 votes
by (93.2k points)
selected by
 
Best answer
Centre of the given circle is C(0,0) and radius is 1. Distance of centre of the circle from the given line is
`CP=(|m(0)-0+2|)/(sqrt(1+m^(2)))=(2)/(sqrt(1+m^(2)))`
If the line cuts the circle at two distinct or coincident points, then
`CP lt1`
`:. (2)/(sqrt(1+m^(2))) le1`
`implies 1+m^(2)ge4`
`implies m^(2)ge3`
`implies m in(-oo,-sqrt(3)]cup[sqrt(3),oo)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...