We have circles
`x^(2)+y^(2)-3x+5y-7=0` (1)
and `2x^(2)+2y^(2)-4x+8y-13=0` (2)
Equation of radical axis of the two circles can be obtained by subtracting the equation of one circle from that of the other in such a way that term `x^(2)` and `y^(2)` gets cancelled out.
So, multiplying equation (1) by 2 and then subtracting equation (2) from it, we get ,brgt `-2x+2y-1=0`
or `2x-2y+1=0`
