From the figure,
`cos theta =(a^(2)+b^(2)-c^(2))/(2ab)`
`:. c=sqrt(a^(2)+b^(2)-2ab cos theta)= C_(1)C_(2)`
Area of triangle `C_(1)AC_(2)=(1)/(2)ab sin theta=(1)/(2)AM xx C_(2)C_(2)`
`:. AM =(ab sin theta)/(sqrt(a^(2)+b^(2)-2ab cos theta))`
`:.` Length of common chord, `AB=2AM=(2ab sin theta)/(sqrt(a^(2)+b^(2)-2ab cos theta))`