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Find the equation of the circle passing through the origin and cutting intercepts of lengths 3 units and 4 unitss from the positive exes.

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Find the equation of the circle passing through the origin and cutting intercepts of lengths 3 units and 4 unitss from the positive exes.
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Correct Answer - `x^(2)+y^(2)-3x-4y=0`
Obviously, (3,0) and (0,4) are the endpoints of diameter.
Then , the equation is `(x-3)(x-0)+(y-0)(y-4)=0 ` i.e.,
`x^(2)+y^(2)-3x-4y=0`
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