Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
571 views
in Mathematics by (91.8k points)
closed by
If the equation `x^2+y^2+2h x y+2gx+2fy+c=0` represents a circle, then the condition for that circle to pass through three quadrants only but not passing through the origin is `f^2> c` (b) `g^2>2` `c >0` (d) `h=0`
A. `f^(2) lt c`
B. `g^(2) gtc`
C. `cgt0`
D. `h =0`

1 Answer

0 votes
by (93.2k points)
selected by
 
Best answer
Correct Answer - 1,2,3,4
The given circle is `x^(2)+y^(2)+2hxy+2gx+2fy+c=0` (i)
For (i) to represent a circle, `h=0`
So, the given circle is
`x^(2)+y^(2)+2gx+2fy+c=0` (ii)
image
For circle (ii) to pass through the quadrants only.
I. Circle must cut x-axis `i.e., g^(2)-c gt0`
II. Circle must cut y-axis `g^(2)-cgt0`
III. The origin should lie outside circle `(ii) , i.e., cgt0`
Therefore, the required conditions are `g^(2) gt c, f^(2) gt c, cgt 0` and `h=0`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...