Let AB be the length of the tangent intercepted by auxiliary circle and `S_(1),S_(2)` be the foci.
Given that
`angleAS_(1)B=angleAS_(2)B`
`rArrangleS_(1)AB=angleS_(2)AB=(pi)/(2)`
So `AS_(1)S_(2)B` is a rectangle.
`:. AB=S_(1)S_(2)=2aex=2xx5xx(3)/(5)=6`