Question

If the midpoint of the chord of the ellipse `x^2/16+y^2/25=1`is `(0,3)`

Answer 1

The equation of the chord chose midpoind is (0,3) is `(3y)/(25)-1=(9)/(25)-1`
i.e., y=3
It intersects th ellipse
`(x^(2))/(16)=(y^(2))/(25)=1`
`:. (x^(2))/(16)=1-(9)/(25)=(16)/(25) or x=+-(16)/(3)`
`:.` Length of chord `=(32)/(5)`