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To neutralize completely 20 mL of 0.1M aqueous solution of phosphorus acid `(H_(3)PO_(3))` the volume of `0.1M` aqueous KOH solution required is

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To neutralize completely 20 mL of 0.1M aqueous solution of phosphorus acid `(H_(3)PO_(3))` the volume of `0.1M` aqueous KOH solution required is
A. 40 mL
B. 20 mL
C. 10 mL
D. 60 mL
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Correct Answer - A
`H_(3)PO_(3)` is a dibasic acid
`N_(1)V_(1)` (acid) `= N_(2)V_(2)` (base)
`0.1xx2xx20=0.1xx1xx V_(2) therefore V_(2)=(0.1xx2xx20)/(0.1xx1)=40 ml`
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