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What will be the value of molality for an aqueous solution of 10% w/W NaOH?

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What will be the value of molality for an aqueous solution of 10% w/W NaOH?
A. `2.778`
B. 5
C. 10
D. `2.5`
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Correct Answer - A
Let mass of solution = 100 g `therefore` Mass of NaOH = 10 g
Mass of solvent = 90 g
`therefore` Molality `=((10)/(40))/((90)/(1000))=(10)/(40)xx(1000)/(90)=2.778`.
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