Correct Answer - A
Molality `=("Number of moles of sollute")/("weight of solvent (in kg)")`
If number of moles of solute = 1
Weight of solvent = 1 kg then, molality = 1, i.e., one molala
For glucose `(C_(6)H_(12)O_(6))` , molecular weight = 180
number of moles `=(180)/(180)=1`, weight of water = 1 kg
Hence, molality of the solution is one.