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A die is thrown three times. Events A and B are defined as below:A : 4 on the third throwB : 6 on the first and 5 on the second throwFind the probability of A given that B has already occurred.

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total otcomes `= 6*6*6 = 216`
`P(A) = 36/216`
`P(B)= 6/216`
`P(A nn B)=1/216`
`P(A|B) = (P(A nn B))/(P(B))`
`=(1/216)/(6/216)= 1/6`

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