Question

Determine the points on the curve `x^2=4y` which are nearest to the point (0,5).

Answer 1

`d=sqrt((x_1-o)^2+(y_1-5)^2)`
`d=sqrt(4y_1+(y_1-5)^2`
`d/(dy_1)=1/(2sqrt(4y_1+(y_1-5)^2))*(4+2(y_1-5))=0`
`4+(2(y_1-5)=0`
`y_1=3`
`x_1^2=4y_1`
`x_1=pm2sqrt3`
Points=`(2sqrt3,3),(-2sqrt3,3).`