Correct Answer - C
First boiling point of water `= 100^(@)C`
Final boiling point of water `= 100.52^(@)`
`w=3g, W=200g, K_(b)=0.6 K-kg mol^(-1)`
`Delta T_(b)=100.52-100=0.52^(@)C`
`m=(K_(b)xx wxx1000)/(Delta T_(b)xx W)`
`=(0.6xx3xx1000)/(0.52xx200)=(1800)/(104)=17.3 gmol^(-1)`.