Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
186 views
in Chemistry by (91.8k points)
closed by
Osmotic pressure of a solution is `0.0821 atm` at a temperature of 300 K. The concentration in mole/litre will be
A. `0.033`
B. `0.066`
C. `0.33xx10^(-2)`
D. 3

1 Answer

0 votes
by (93.2k points)
selected by
 
Best answer
Correct Answer - C
`pi=CRT, C=(pi)/(RT)=(0.0821)/(0.0821xx300)=0.33xx10^(-2)`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...