Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
642 views
in Chemistry by (91.8k points)
closed by
Dissolving 120g of urea (mol.wt.60) in 1000g of water gave a solution of density 1.15 g/mL. The molarity of the solution is
A. 1.78 M
B. 2.00 M
C. 2.05 M
D. 2.22 M

1 Answer

+1 vote
by (93.2k points)
selected by
 
Best answer
Correct Answer - C
Mole `=(120)/(60)=2`
mass of solution = 1120 g
`V=(1120)/(1.15xx100)=(112)/(115)L`
`M=(2xx115)/(112)=2.05` mol/litre

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...