Question

Gaseous mixture of contains 56 g of `N_(2)` , 44g of `CO_(2)` and 16 g of `CH_(4)` . The total pressure of mixture is 720 mm of Hg . The partial pressure of `CH_(4)` is :-
A. 75 atm
B. 160 atm
C. 180 atm
D. 215 atm

Answer 1

Correct Answer - C
First of all we have to calculate the number of moles.
Number of moles of `N_(2)=(56)/(28)=2`
Number of moles of `CO_(2)=(44)/(44)=1`
`:. `Total number of moles `= 2=1+1=4`
`:. `mole fraction of `CH_(4)=(1)/(4)`
`:. ` partial pressure of `CH_(4)`
`=` mole fraction of `CH_(4) xx` total pressure
`=(1)/(4) xx 720 = 180` atm.