Correct Answer - A
In isolated system the expansion of gas is carried out adiabatically. Since heat exchange between system and surrounding is not possible i.e., `q=0` and secondary `w_(rev)` is always greater than `w_(irr)` therefore for reversible process there must be comparatively higher decreases in internal energy i.e, `Delta U` for reversible process will be more negative. Hence final temperature in reversible process will be smaller than irreversible process.
`:. (T_(f))_("irrev") gt (T_(f))_(rev)`