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For the reaction `H_(2)+I_(2)hArr2Hl,` the equilibrium concentration of `H_(2),I_(2)and HI` are `8.0. 3.0 and 28.0` mol per litre respectively, the equlibrium constant of the reaction is
A. `30.66`
B. `32.66`
C. `34.66`
D. `36.66`

1 Answer

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Best answer
Correct Answer - B
`K_(c)=([HI]^(2))/([H_(2)][I_(2)])=((28)^(2))/(8xx3)=32.66`

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