Correct Answer - A
At equlibrium number of moles of `H_(2)=0.2` moles 0.8 moles of `H_(2)` reacts with `(2-0.8)` moles of `I_(2)` to from `(2xx0.8)` moles of HI
`H_(2)+I_(2)hArr2HI`
`{:("Inital no.",1,2,0),("of mole",,,),("No of moles"0.,2,,(-20.8)2xx0.8),("at equlibrium",,=1.2,=1.6):}`