Question

One mole of ethyl alcohol was treated with one mole of acetic acid at `25^(@)C.` Two-third of the alcohol change into easter at equlibrium. The equlibrium constant for the reaction will be
A. 1
B. 2
C. 3
D. 4

Answer 1

Correct Answer - D
`C_(2)H_(2)OH+COOHtoCH_(3)COOC_(2)H_(5)+H_(2)O`
`{:("Initial conc.","1 mol","1 mol","0 mole","0 mole"),("At equlibrium", 1-2/3=1/3 "mol",1/3"mol",2/3"mol",2/3"mol"):}`
`K_(C)=((2)/(3)xx(2)/(3))/(1/2xx1/3)=4`