Question

The equilibrium constant `K_(c)` for the reaction `SO_(2)(g)+NO_(2)(g)hArrSO_(3)(g)+NO(g) ` is 16. If one mole of all four gases is taken in a one litre container, the equilibrium concentration of `SO_(3)` would be
A. `0.4m`
B. `0.6m`
C. `1.4m`
D. `1.6m`

Answer 1

Correct Answer - D
Given `SO_(2(g))+NO_(2(g))to SO_(3(g))+NO_((g))`
`{:("At initial concentration", "1 mole", "1 mole", "1 mole", "1 mole"),("At equlibrium concentration","1-x mole","1-x mole", "1+ mole", "1+ mole"):}`
Applying law of mass action,
`K_(c)=([SO_(3)][NO])/([SO_(2)][NO_(2)])=((1+x)(1+x))/((1-x)(1-x))=16`
`or ((1+x)^(2))/((1-x)^(2))=16or(1+x)/(1-x)=4`
`1+x=4-4x`
`5x=3, i.e.,x=3//5=0.6`
`"conc. of" SO_(3) "at equlibrium"=1+x=1+0.6=1.6"mole"`