Question

Phosphrus penachloride disociates as follows, in a closed reaction vessel, `PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))` If total pressur at equilibrium of the reaction mixture is P and degree of dissociation of `PCl_(5)` is x, the partial pressure of `Pcl_(3)` will be
A. `((x)/(x-1))P`
B. `((2x)/(1-x))P`
C. `((x)/(x-1))P`
D. `((x)/(1-x))P`

Answer 1

Correct Answer - A
`{:(PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))),(1" "0" "0),((1-x)" "x " "x):}`
`therefore"Partial pressure of" PCl_(3)=((x)/(x+1))P`