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3 mole of A and 4 moles of B are mixed together and allowed to come into equilibrium according to the following reaction `3A_((g))+4B_((g))hArr2C_((g))+3D_((g))`
A. `1//4`
B. `1//3`
C. `1//2`
D. 1

1 Answer

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Best answer
Correct Answer - C
`3A+4BhArr2C+3D`
`impliesK_(1)=([C]^(2)[D]^(3))/([A]^(3)[B]^(4))" "...(i)`
When moles of `C=1` the equation becomes
`3/2A+2BhArrC+3/2D`
`impliesK_(2)=([C][D]^(3//2))/([A]^(3//2)[B]^(2))" "...(ii)`
On comparing Eq. (i) with Eq. (ii), we get
`K_(2)^(2)=K_(1)^(2)or K_(2)=(K_(1))^(1//2)`
Hence, equlibrium extent`=1/2`

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