Question

Some solid `NH_(4)HS` is placed in a flask containing `0.5` atm of `NH_(3),` what would be pressure of `NH_(3)and H_(2)S` when equilibrium is reached
`NH_(4)HS_((g))hArrNH_(3(g))+H_(2)S_((g)),K_(p)=0.11`
A. `6.65` atm
B. `0.665` atm
C. `0.0665` atm
D. `66.5` atm

Answer 1

Correct Answer - B
`NH_(4)HShArrNH_(3)+H_(2)S`
`0.5+x x`
`(0.5+x)=0.11`