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`int sin^(-1) (cosx) dx = ?`

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`int sin^(-1) (cosx) dx = ?`
A. `cosec x + C`
B. `(pix)/(2) +(x^(2))/(2) + C`
C. `(pix)/(2) - (x^(2))/(2) + C`
D. `(x^(2))/(2) - (pix)/(2) + C`
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1 Answer

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Correct Answer - C
`sin^(-1) (cosx) = sin^(-1) {sin(pi/2 - x)} = (pi/2 - x)`.
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