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The `pk_(a)` of a weak acid, HA is 4.8. The `pK_(b)` of a weak base, BOH is 4.78. The pH of an aqueous solution of the corresponding salt, BA will be
A. 4.79
B. 7.01
C. 9.22
D. 9.58

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Correct Answer - B
`pK_(a) = 4.8 , pK_(b) = 4.78`
`pH = 7+(1)/(2)(pK_(a) - pK_(b)) = 7 + (1)/(2)(4.8 - 4.78) = 7.01`.

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