Question

An alcoholic drink substance pH = 4.7 then OH ion concentration of this solution is `(K_(w) = 10^(-14) mol^(2)//l^(2))`
A. `3 xx 10^(-10)`
B. `5 xx 10^(-10)`
C. `1 xx 10^(-10)`
D. `5 xx 10^(-8)`

Answer 1

Correct Answer - B
pH = 4.7
pH + pOH = 14, pH = 14- 4.7 , pOH = 9.3
`[OH^(-)] = "Antilog" [-9.3] [OH^(-)] = 5 xx 10^(-10)`.