Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.5k views
in Mathematics by (92.4k points)
closed by
Evaluate `int(dx)/(sqrt(x(1-2x)))`.
A. `(1)/(sqrt(2))sin^(-1)(2x-1)+C`
B. `(1)/(sqrt(2))sin^(-1)(2x+1)+C`
C. `(1)/(sqrt(2))sin^(-1)(4x+1)+C`
D. `(1)/(sqrt(2))sin^(-1)(4x-1)+C`

1 Answer

0 votes
by (91.6k points)
selected by
 
Best answer
Correct Answer - D
`x(1-2x)=(x-2x^(2))=2((x)/(2)-x^(2))=2[(1)/(16)-(x^(2)-(x)/(2)+(1)/(16))]=2[((1)/(4))^(2)-(x-(1)/(4))^(2)]`
`therefore I=(1)/(sqrt(2))int(dx)/(sqrt(((1)/(4))^(2)-(x-(1)/(4))^(2)))=(1)/(sqrt(2)).int(dx)/(sqrt(((1)/(4))^(2)-t^(2))),"where" (x-(1)/(4))=t`
`=(1)/(sqrt(2))sin^(-1)""(t)/(((1)/(4)))+C=(1)/(sqrt(2))sin^(-1)4t+C=(1)/(sqrt(2))sin^(-1){4(x-(1)/(4))}+C`
`=(1)/(sqrt(2))sin^(-1)(4x-1)+C.`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...