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0.1 M HCl and `0.1 M H_(2)SO_(4)`, each of volume 2 ml are mixed and the volume is made up to 6 ml by adding 2ml of 0.01 N NaCl solution. The pH of the resulting mixture is
A. 1.17
B. `1.0`
C. 0.3
D. log 2 - log 3

1 Answer

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Best answer
Correct Answer - B
Millimoles of `H^(+) = 0.1 xx 2 + 0.1 xx 2 xx 2 = 0.6`
Total volume in ml = 6
`pH = -log [H^(+)] = -log ((0.6)/(6)) = -log 0.1 = 1.0`.

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