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The pH of a 0.01 M solutions of acetic acid having degree of dissociation 12.5% is
A. 5.623
B. 2.903
C. 3.723
D. 4.509

1 Answer

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Correct Answer - B
`[H^(+)] = C alpha = 0.01 xx (1.25)/(100)`
`H^(+) = 1.25 xx 10^(-3)`, pH = between 2 or 3 = 2.90.

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