Question

Entropy changes for the process, `H_(2)O_((l))rarrH_(2)O_((s))` at normal pressure and 274 K are given below `DeltaS_("system")=-22.13`, `DeltaS_("surr")=+22.05`, the process is non-spontaneous because
A. `DeltaS_("system") " is " -ve`
B. `DeltaS_("surr")" is +ve"`
C. `DeltaS_(u)" is -ve"`
D. `DeltaS_("system")ne DeltaS_("surr")`

Answer 1

Correct Answer - C
`DeltaS_(u)=DeltaS_("system")+DeltaS_("surrounding")=-22.13+22.05 =-0.08`
For a spontaneous process, `DeltaS_(u)` must be positive i.e.,
`DeltaS_(u)=DeltaS_("system")+DeltaS_("surrounding")gt0`.